c - Why the division of two integers return 0.00? -

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• printf(“%f”, aa) when aa of type int [duplicate] 2 answers

every time run program different , weird results. why that?

#include <stdio.h>  int main(void) {     int = 5, b = 2;     printf("%.2f", a/b);     return 0; } 

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printf("%.2f", a/b); 

the output of division again of type int , not float.

1. you using wrong format specifier lead undefined behavior.
2. you need have variables of type float perform operation doing.

the right format specifier print out int %d