Python: regex findall -

iam using python regex extract values given string. string:

mystring.txt

sometext somemore    text here   other text                course: course1 id              name                marks ____________________________________________________ 1               student1            65 2               student2            75 3               myname              69 4               student4            43                course: course2 id              name                marks ____________________________________________________ 1               student1            84 2               student2            73 8               student7            99 4               student4            32                course: course4 id              name                marks ____________________________________________________ 1               student1            97 3               myname              60 8               student6            82 

and need extract course name , corresponding marks particular student. example, need course , marks myname above string.

i tried:

re.findall(".*?course: (\w+).*?myname\s+(\d+).*?",buff,re.dotall) 

but works if myname present under each course, not if myname missing in of course, in example string.

here output as: [('course1', '69'), ('course2', '60')]

but want achive is: [('course1', '69'), ('course4', '60')]

what correct regex this?

#!/usr/bin/python     import re  buffer_fp = open("mystring.txt","r+") buff = buffer_fp.read() buffer_fp.close() print re.findall(".*?course: (\w+).*?myname\s+(\d+).*?",buff,re.dotall) 

.*?course: (\w+)(?:(?!\bcourse\b).)*myname\s+(\d+).*?                      ^^^^^^^^^^^^ 

you can try this.see demo.just use lookahead based quantifier search myname before course before it.

https://regex101.com/r/pg1ku1/26