c# - XML Deserialization from attributes to properties -

how can deserialize xml this:

<query>   <parameters>     <param name="lastupdate">2012-05-25</param>     <param name="code">11222122</param>     <param name="type">idnlookup</param>   </parameters>   <response>     <category name="person" version="1">       <field name="surname">soap</field>       <field name="name1">joe</field>       <field name="date_of_birth">1973-05-09</field>     </category>     <category name="contact" version="1">       <row>         <field name="phone">0118063433</field>         <field name="type">home</field>         <field name="date">2003-01-01</field>       </row>       <row>         <field name="phone">0124666566</field>         <field name="type">home</field>         <field name="date">2008-03-11</field>       </row>    </category>   </response> </query> 

into class structure this:

public class query{  public string lastupdate {get;set;}  public string code {get;set;}  public string type {get;set;}  public response response {get;set;} } class response{   public person person {get;set;}   public contact[] contacts {get;set;} } class person {   public string surname {get;set;}   public string name1 {get;set;}   public string date_of_birth {get;set;} } class contact {   public string phone {get;set;}   public string type {get;set;}   public string date {get;set;} } 

using standard .net xml serializer. or need roll own?

to expand on simon's xslt idea, consider following xslt:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">   <xsl:output method="xml" indent="yes"/>    <xsl:template match="@* | node()">     <xsl:copy>       <xsl:apply-templates select="@* | node()"/>     </xsl:copy>   </xsl:template>   <xsl:template match="/query/parameters">     <xsl:apply-templates select="*"/>     <!-- removes level hierarchy applying directly -->   </xsl:template>   <xsl:template match="*[@name]">     <xsl:element name="{@name}">       <xsl:apply-templates select="@*[name()!='name'] | * | text()"/>     </xsl:element>   </xsl:template> </xsl:stylesheet> 

the key match here *[@name], takes of form:

<foo name="abc" ...>...</foo> 

and rewrites as:

<abc ...>...</abc> 

this transforms xml to:

<query>   <lastupdate>2012-05-25</lastupdate>   <code>11222122</code>   <type>idnlookup</type>   <response>     <person version="1">       <surname>soap</surname>       <name1>joe</name1>       <date_of_birth>1973-05-09</date_of_birth>     </person>     <contact version="1">       <row>         <phone>0118063433</phone>         <type>home</type>         <date>2003-01-01</date>       </row>       <row>         <phone>0124666566</phone>         <type>home</type>         <date>2008-03-11</date>       </row>     </contact>   </response> </query> 

which can mapped model minor tweaks attributes:

[xmlroot("query")] // <==== add public class query {...}  [xmlarray("contact"), xmlarrayitem("row")] // <=== add public contact[] contacts { get; set; } 

which can used, example:

static void main() {     xslcompiledtransform xslt = new xslcompiledtransform();     xslt.load("my.xslt");     var sw = new stringwriter();     xslt.transform("my.xml", null, sw);     var transformedxml = sw.tostring();      console.writeline(transformedxml);     query query;     using (var reader = xmlreader.create(new stringreader(transformedxml)))     {         query = (query)new xmlserializer(typeof(query)).deserialize(reader);     }     // query populated }