asp.net mvc 3 - how to pass grid view data to the other view as per selected id -

//this web grid  using (html.beginform()) {     <div id="content">         @grid.gethtml(           tablestyle: "webgrid-table",           headerstyle: "webgrid-header",           footerstyle: "webgrid-footer",//properties           alternatingrowstyle: "webgrid-alternating-row",//this            rowstyle: "webgrid-row-style",           columns: grid.columns(               grid.column(header: "job_id", format: @<text><div>@(item.webgrid.rows.indexof(item) + 1)</div></text>),               grid.column(columnname: "location", header: "location"),               grid.column(columnname: "jobtitle", header: "jobtitle"),               grid.column(columnname: "technology", header: "technology"),               grid.column(columnname: "job_description", header: "job_description"),               grid.column(columnname: "category", header: "category"),               //this link navigating next page selected id                                                                grid.column(columnname: "apply",format:@<text>@html.actionlink("apply", "jobdetails", "client")</text>)          ))     </div> } 

if understood problem correctly may help:

extract grid component partial view , can reused where.

if mean extracting data only, have use jquery ajax pick data of interest.