css - Sass converts black automatically to #000000 -

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• why sass change format of colors? 2 answers

i'm writing mixin add multiple fonts in 1 line. in mixin write weights want use this:

$font-weights: ( "hairline": 100, "thin": 200, "light": 300, "regular": 400, "medium": 500, "semibold": 600, "bold": 700, "heavy": 800, "black": 900,    ); $main-font: "lato"; @include font-list($main-font,hairline thin light regular medium semibold bold heavy black, normal, $font-weights); 

the last weight in list of weights given in @include "black", links go well, mixin use gives error on last value, because in way converts "black" automatically before using #000000.

is there way make sass not this?

the mixin(s):

@mixin font-include($name, $file, $weight, $type) {     @include font-face("#{$name}", font-files("#{$file}.woff", "#{$file}.ttf"), "#{$file}.eot", $weight, $type); }  @mixin font-list($name,$weights,$type,$font-weight){     @for $i 1 through length($weights) {                @include font-include($name,#{$name}-#{nth($weights,$i)},map-get($font-weight,#{to-lower-case(nth($weights,$i))}),$type);     } } 

the error given compass is:

 $string: #000000 not string `to-lower-case' 

fixed using unquote in mixin on weights.

(and added functionality italic fonts).

@mixin font-list($name,$weights,$type,$font-weight){     $italic: '';     @if $type == 'italic'{           $italic: 'italic';     }     @for $i 1 through length($weights) {            $weight: unquote("#{nth($weights,$i)}");         @include font-include($name,#{$name}-#{nth($weights,$i)}#{$italic},map-get($font-weight,#{to-lower-case($weight)}),$type);     } }