Java integer to hex and to int -

i have problem, method not work expected. in cases works. there case not work. have byte array containing values. in hex e.g.: 0x04 0x42 (littleendian). if use method converttwobytestoint, small number. should > 16000 , not smaller 2000.

i have 2 methods:

private static int converttwobytestoint(byte[] a){     string f1 = convertbytetohex(a[0]);     string f2 = convertbytetohex(a[1]);     return integer.parseint(f2+f1,radix16); }  private static byte[] convertinttotwobyte(int value){     byte[] bytes = bytebuffer.allocate(4).putint(value).array();     system.out.println("check: "+arrays.tostring(bytes));     byte[] result = new byte[2];     //big little endian:     result[0] = bytes[3];     result[1] = bytes[2];     return result; } 

i call them follows:

    byte[] h = convertinttotwobyte(16000);     system.out.println("ats: "+arrays.tostring(h));     system.out.println("tbtint: "+converttwobytestoint(h)); 

if use value 16000, there no problem, if use 16900, integer value of "converttwobytestoint" 1060.

any idea?

based on example provided, guess convertbytetohex(byte) converting single-digit hex string when byte value less 0x10. 16900 0x4204 , 1060 0x424.

you need ensure conversion zero-padded 2 digits.

a simpler approach use bit manipulation construct int value bytes:

private static int converttwobytestoint(byte[] a) {     return ((a[1] & 0xff) << 8) | (a[0] & 0xff); }